AnnDee4444
Well-Known Member
I've seen these numbers listed:Maybe, but I honestly can't figure it out. The Ram website states 130lb/ft torque for the 5.7 v8 and other places confirm, with 90lb/ft for the v6..
"It provides a brief torque boost of 90 lb-ft in V-6 RAMs and 130 lb-ft in V-8 models."
https://greencarjournal.com/technology/how-ram-etorque-works/
Wait, found it! Think this would explain how they get 90lb/ft of torque from the 45 created by the generator..
"It does provide power to initially start the vehicle moving — 12 horsepower for the V-6 and 16 for the V-8. Torque output of 39 lb/ft for the V-6 is multiplied by the belt drive to create a 90 lb/ft assist and the V-8 version creates 49 lb/ft, again multiplied by the belt for an assist of 130 lb/ft."
https://www.vehicleservicepros.com/.../a-look-at-the-ram-1500-etorque-a-mild-hybrid
You'd think this would be interesting shit that Jeep/Ram would want to advertise and more clearly explain to consumers themselves. ?‍![]()
5.7 = 130 lb.ft.
3.6 = 90 lb.ft.
2.0 = 70 lb.ft.
The torque multiplication by the belt is probably used for marketing purposes to get the BSG's rating at the crankshaft. Also I've always thought that the larger motor (with more rotating mass) is what dictates more torque... so that the restart times are similar.
What I really want to know is if the 130 lb.ft. unit can be Frankensteined onto my 2.0, and made to operate until about 2,500 crankshaft RPM.
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