GATORB8
Well-Known Member
A bit theoretical since it assumes the spring bind doesn't bump stop. At full articulation, without modified bump stops, the shocks are in the same place and same stroke. So the stuffed tire is in the same locationas stock at full compression and the drooped tire is in the same location as stock at full extension.This is confusing to me. If you're only lifting the body, or anything for that matter, how could the COG possibly be lower. You're moving weight higher which would necessitate the COG moving upwards as well. Also, axle rotation...how would that be 2" higher at full stiff? None of these methods of lifting increase the height of the axle from the ground, only the body off of the axle. The only way to do that is with larger tires. When you talk about axle rotation, it may go up if the driver side tire stays at the same surface height and the passenger side travels up over a log/bump/rock/hill. But even then, the full travel would be less than the entire lift as the center wouldn't move as much as the extreme ends. Please help me out here...
With the stops + extensions, the stuffed one is 2" further from the frame, and the drooped one is 2" further from the frame.
Since the axle is basically a line between those two points, it's 2" further from the frame along the whole axle.
Axle ground clearance doesn't change, so the only change would be the frame/body being closer to the axle/ground in the first example. As such, the COG would be lower and the clearance from the ground to the frame mounted components would be closer when fully articulated.
COG and frame clearance would gain the 2" in both lift situations at flat ride height.
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