In an open differential, whichever side is on the inside of a turn is driving.It does feel like the rear passenger is the main wheel indeed, but hard to say with the BLD nowadays.
More details please. This occurred after driving about how many miles after having new tires installed? Or was it during installation? Wheels and lug nuts are OEM? Improperly torqued lug nuts, way too loose, or way, way too tight might have been at fault.Snapped lugs off ruining the wheel after new tires mounted.
Just jack both wheel on the back disable LSD and BLD and look at what wheel will spin when you apply throttle / rotate the shaft. the wheel spinning in accordance to input direction is the primary wheel. it is also the one that will do the burnoutIn an open differential, whichever side is on the inside of a turn is driving.
Not sure why it matters, snapping lugs is most likely an installation error.
So we’re thinking the 3.6 minivan motor has so much torque at the rear wheels it can shear wheel studs. I know mine doesn’tJust jack both wheel on the back disable LSD and BLD and look at what wheel will spin when you apply throttle / rotate the shaft. the wheel spinning in accordance to input direction is the primary wheel. it is also the one that will do the burnout![]()
The other day I did some "11" while trying to insert myself in traffic, ya color me surprised on that one.So we’re thinking the 3.6 minivan motor has so much torque at the rear wheels it can shear wheel studs. I know mine doesn’t![]()
how you explain one wheel burnout if both receive the same amount of power ?Both rear wheels receive the exact same amount of power. The passenger side wheel tends to appear to be the primary due to the rotation of the engine, transmission and driveshaft.
When torque is applied the rotational force forces the drivers side of the axle down and the passenger side up, thus increasing traction on the drivers side and reducing traction on the passenger side which results in that side tire spinning easier.
One breaks traction first, then that one receives the majority of the power.how you explain one wheel burnout if both receive the same amount of power ?
Than they do not receive the same amount of power if one receive 100% of it.One breaks traction first, then that one receives the majority of the power.
I thought I did a decent job explaining it in my previous post.how you explain one wheel burnout if both receive the same amount of power ?
Ok, but if both receive the same amount of torque they should both have the same rotational force pushing both of them down no ?I thought I did a decent job explaining it in my previous post.