Rock Sponsor (Level 1)
Yes it does, I show the case where the scale in the back went up to 75 from the original 50. But the load in the springs did not change because the control arm starts picking up load. Also notice that the only way for the scale to increase is if the scale remains horizontal. 0 friction. To do that the scale is no longer in direct line with the springs.Please answer the question posed. Do you believe the weight on the scales goes up, down or stays the same?
The original question is if the rear springs compress as the grade of the slope increases. Now bring the books.Oh boy, you're going to make me get out my physics textbook. Pretty sure the diagrams above are not quite accurate but I haven't done the math. I'm assuming the wheels are locked (i.e., they won't either slide or roll?)
If the wheels can move at all, then it becomes a dynamics problem and that's about 2 years more of college to solve.
Weigh has nothing to do with anything . It’s normal force.Weight would stay the same
They compress as you put weight on them. BUT the weight has to be in the same direction the springs is facing. That’s the point of the drawing. The force still vertical but the spring is now inclined. It actually receives less weight.So, if you're conceding that the weight goes up on the rear tires as the front end is raised, the next question is a general one: why do springs compress?
In your case the floor remains the same. The point of contact of the tire with the ground changes. If you were to lift the whole garage ( like the car going up a ramp) so the points of contact of the tires remain the same, you would not see a compression on the springs.Nice to meet you as well..and I don't mind being wrong...I'd just like an explanation b/c I'm not seeing what you're saying. It sounds like you're using a much more dynamic (and therefore, realistic) model than I am but I was being overly simplistic in an attempt to explain the concept.
Here's the thing:
I just was out in the shop and lifted the rear of my buggy (air pressure all at 5 psi) 7.5" off the ground (jack ran out of travel before I could get any higher). The front c/o springs compressed 1/4" on each side (went from 6" from the shock body to center of mounting eye on the driver side to 5 3/4" and from 5 3/4" on the passenger to 5.5"). At that pressure, the tires probably squished more than that....but the point is: the weight transferred to the front by raising the back and the springs did compress.
I was out there working on the wife's JL since we broke a bolt on her beadlock...I needed to pull the driver rear tire anyway...figured I'd repeat the procedure.
Long story short, the front springs compressed 3/8-1/2" (depending on the side) with the tires at 36 psi. I didn't measure how high the rear tires were off the ground...just went till I ran out of jack.
So far, from what I can tell, everything I stated was accurate. If it wasn't, please....please....correct me. I don't want to spread false information to anyone about anything.
Also weight is not centered, different angle may move the center of mass relatively forward or backward. Spring force changes as the spring is compressed. Geometry in the rear suspension probably differs from the geometry in the front. Too many variables.And I can imagine (I didn't check) that the rear, while being lifted, is being compressed that same 1/4" amount I noted on the front end with the rear elevated vs. the front, but there's also a lot of suspension geometry going on here as well in a more dynamic model as when you're climbing something the anti-squat, IC, and roll centers (etc.) will all come into play, especially if the axles are articulating to any significant degree.